Search a deeply nested value in array of objects in javascript -


i'm trying implement search given value should in array of object key values(there can nested objects). here example. below function take object , query search in array objects key values. so, if match found should filter array.

function searchobj (obj, query) {   (var key in obj) {     var value = obj[key];     if (typeof value === 'object') {        searchobj(value, query);     }     if (typeof value === 'string' && value.tolowercase().indexof(query.tolowercase()) > -1) {        return obj;     }   } }

here dummy data

var demodata=[   {id:1,desc:{original:'trans1'},date:'2017-07-16'},   {id:2,desc:{original:'trans2'},date:'2017-07-12'},   {id:3,desc:{original:'trans3'},date:'2017-07-11'},   {id:4,desc:{original:'trans4'},date:'2017-07-15'} ];

here array i'm filtering object of match

var searchfilter = demodata.filter(function(obj){      return searchobj(obj, 'trans1'); }); console.log(searchfilter);

for example: if call searchobj(obj,'2017-07-15') returns particular object if search trans1 or trans should object , return match. i'm kinda stuck appreciated. thanks.

case 1 working because not hitting recursion. in case 2, keep searching after found result.

return object once find. 

if (typeof value === 'object') {        return searchobj(value, query);     }     if (typeof value === 'string' && value.tolowercase().indexof(query.tolowercase()) > -1) {        return obj;     } 

function searchobj (obj, query) {      (var key in obj) {      var value = obj[key];      if (typeof value === 'object') {         return searchobj(value, query);      }      if (typeof value === 'string' && value.tolowercase().indexof(query.tolowercase()) > -1) {         return obj;      }    }  }    var demodata=[    {id:1,desc:{original:'trans1'},date:'2017-07-16'},    {id:2,desc:{original:'trans2'},date:'2017-07-12'},    {id:3,desc:{original:'trans3'},date:'2017-07-11'},    {id:4,desc:{original:'trans4'},date:'2017-07-15'}  ];    var searchfilter = demodata.filter(function(obj){       return searchobj(obj, 'trans1');  });  console.log(searchfilter);


Comments

Post a Comment

Popular posts from this blog

python - Operations inside variables -

this question has answer here: evaluating mathematical expression in string 12 answers i want make python script finds maximum possible output using 2 operations. problem says there syntax error @ 2nd last line, in b in there. how can fix it? x = 0 = int(input("1st number:")) c = int(input("2nd number:" )) e = int(input("3rd number:" )) in range(4): if == 0: b = "+" elif == 1: b = "-" elif == 2: b = "/" else: b = "*" j in range(4): if j == 0: d = "+" elif j == 1: d = "-" elif j == 2: d = "/" else: d = "*" k = b c d e print(k) if you're after variables e on single line, couldn...
Read more

Generic Map Parameter java -

i having lot of methods of type: public static list<eduusers> getdetails(class c, map<string, integer> params) { list<eduusers> details = null; session session = hibernateutil.getsessionfactory().opensession(); transaction tx = null; try { tx = session.begintransaction(); criteria cr = session.createcriteria(c); (map.entry<string, integer> entry : params.entryset()) { cr.add(restrictions.eq(entry.getkey(), entry.getvalue())); } details = cr.list(); tx.commit(); } catch (exception asd) { log.debug(asd.getmessage()); if (tx != null) { tx.commit(); } } { session.close(); } return details; } i trying have generic method them , have written far: public static <t> list<t> getdetails(class<t> c, class<t> b) { l...
Read more

arrays - What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? -

what arrayindexoutofboundsexception mean , how rid of it? here code sample triggers exception: string[] name = {"tom", "dick", "harry"}; for(int = 0; i<=name.length; i++) { system.out.print(name[i] +'\n'); } your first port of call should documentation explains reasonably clearly: thrown indicate array has been accessed illegal index. index either negative or greater or equal size of array. so example: int[] array = new int[5]; int boom = array[10]; // throws exception as how avoid it... um, don't that. careful array indexes. one problem people run thinking arrays 1-indexed, e.g. int[] array = new int[5]; // ... populate array here ... (int index = 1; index <= array.length; index++) { system.out.println(array[index]); } that miss out first element (index 0) , throw exception when index 5. valid indexes here 0-4 inclusive. correct, idiomatic for statement here be: for (int index = 0; index <...
Read more