python - Why does a very small number return 'inf' instead of the real number? -


i run update of 2 variables (h1 , h2) expected give similar result 1 of them (h2) encounter runtimewarning: overflow encountered in double_scalars 35th iteration. tracked , found there part in h equation can return 1.48219693752e-323 while h2 return inf causes equation error @ iteration .

1.48219693752e-323 in range between (-1.79769313486e+308, 1.79769313486e+308). why 1 of them return inf? happened here?

extra info: 

for in xrange(36): # 35 iterations     k in xrange(kk):         j in xrange(jj):             # update auxiliary             gamma = h             gamma2 = h2             # update h             h[k,j] = (gamma[k,j]/(2*lagrange)) * \                      (( np.sqrt((sum(w[:,k]))**2 + \                      (4*lagrange)*sum(v[:,j]*w[:,k]/np.dot(w[:,:],h[:,j]))) ) - \                      sum(w[:,k]))             h2[k,j] = (gamma2[k,j]/(2*lagrange)) * \                      (( np.sqrt((sum(w[:,k]))**2 + \                      ((4*lagrange/h2[k,j])*sum(gamma2[k,j]*v[:,j]*w[:,k]/np.dot(w[:,:],h2[:,j])))) ) - \                      sum(w[:,k]))             print h == h2             print "for h: ", it, gamma[k,j], v[:,j]*w[:,k], sum(gamma[k,j]*v[:,j]*w[:,k])             # gamma2[k,j] changes inf @ 35th iteration gamma[k,j] fine             print "for h2: ", gamma2[k,j], v[:,j]*w[:,k], sum(gamma2[k,j]*v[:,j]*w[:,k])

if wonder why should give similar result because h2 has gamma2[k,j] in sum (which should pull out coefficient) , should divided h2[k,j](the term in front of sum) h2=gamma2.


Comments

Post a Comment

Popular posts from this blog

python - Operations inside variables -

this question has answer here: evaluating mathematical expression in string 12 answers i want make python script finds maximum possible output using 2 operations. problem says there syntax error @ 2nd last line, in b in there. how can fix it? x = 0 = int(input("1st number:")) c = int(input("2nd number:" )) e = int(input("3rd number:" )) in range(4): if == 0: b = "+" elif == 1: b = "-" elif == 2: b = "/" else: b = "*" j in range(4): if j == 0: d = "+" elif j == 1: d = "-" elif j == 2: d = "/" else: d = "*" k = b c d e print(k) if you're after variables e on single line, couldn...
Read more

Generic Map Parameter java -

i having lot of methods of type: public static list<eduusers> getdetails(class c, map<string, integer> params) { list<eduusers> details = null; session session = hibernateutil.getsessionfactory().opensession(); transaction tx = null; try { tx = session.begintransaction(); criteria cr = session.createcriteria(c); (map.entry<string, integer> entry : params.entryset()) { cr.add(restrictions.eq(entry.getkey(), entry.getvalue())); } details = cr.list(); tx.commit(); } catch (exception asd) { log.debug(asd.getmessage()); if (tx != null) { tx.commit(); } } { session.close(); } return details; } i trying have generic method them , have written far: public static <t> list<t> getdetails(class<t> c, class<t> b) { l...
Read more

arrays - What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? -

what arrayindexoutofboundsexception mean , how rid of it? here code sample triggers exception: string[] name = {"tom", "dick", "harry"}; for(int = 0; i<=name.length; i++) { system.out.print(name[i] +'\n'); } your first port of call should documentation explains reasonably clearly: thrown indicate array has been accessed illegal index. index either negative or greater or equal size of array. so example: int[] array = new int[5]; int boom = array[10]; // throws exception as how avoid it... um, don't that. careful array indexes. one problem people run thinking arrays 1-indexed, e.g. int[] array = new int[5]; // ... populate array here ... (int index = 1; index <= array.length; index++) { system.out.println(array[index]); } that miss out first element (index 0) , throw exception when index 5. valid indexes here 0-4 inclusive. correct, idiomatic for statement here be: for (int index = 0; index <...
Read more