c - How to output a string, the result is (null)? -


this question has answer here:

how output pointer string, print result "(null)" outputting char?

printf("%s\n", *str ? str : "(null)");

if first character pointed str '\0', above print (null). otherwise, print string pointed str.

to handle case:

char *str = null;

...use:

printf("%s\n", (str && *str)?str:"(null)");

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