angularjs - New to Typescript & Angular problems with Http Post -


i'm new angular , typescript , try create simple login page. i've created service in typescript invoked when user presses 'login' button. textboxes contains username , password bound correctly model, when send request backend written in c#, not hit breakpoint suspect because of format of message being sent on wire.

so using postman, i'm able invoke service , access_token when exporting request code in postman nodejs variant like:

var request = require("request");  var options = { method: 'post',   url: 'http://localhost:8081/login',   headers:     { 'postman-token': '34dd4d0f-ff16-db4f-ebae-dab945729410',      'cache-control': 'no-cache',      'content-type': 'application/x-www-form-urlencoded' },   form: { username: 'test', password: 'test', grant_type: 'password' } };  request(options, function (error, response, body) {   if (error) throw new error(error);    console.log(body); });

and typescript code

login(username: string, password:string) : observable<boolean> {          var headers = new headers();         headers.append('content-type', 'application/x-www-form-urlencoded')          var content = json.stringify({             username: username,              password: password,             grant_type: this.grant_type         });          return this.http.post(this.authenticationendpoint, content, {headers: headers})                 .map((response:response) =>  {                      let token = response.json() && response.json().token;                     if(token){                         //this.token = token;                         localstorage.setitem('user', json.stringify({username: username, token:token}));                         return true;                     }                      return false;                 });             }

this results in error in visual studio code, says:

enter image description here

i'm not sure how should interpret error message, since method in webservice not invoked i'm pretty sure has http headers or format of http post.. ideas?

using urlsearchparams body of request , angular automatically set content type application/x-www-form-urlencoded

import { urlsearchparams } "@angular/http"      let body = new urlsearchparams();     body.set('username', username);     body.set('password', password);     .....   this.http.post(this.authenticationendpoint, body).map(..)

Comments

Post a Comment

Popular posts from this blog

python - Operations inside variables -

this question has answer here: evaluating mathematical expression in string 12 answers i want make python script finds maximum possible output using 2 operations. problem says there syntax error @ 2nd last line, in b in there. how can fix it? x = 0 = int(input("1st number:")) c = int(input("2nd number:" )) e = int(input("3rd number:" )) in range(4): if == 0: b = "+" elif == 1: b = "-" elif == 2: b = "/" else: b = "*" j in range(4): if j == 0: d = "+" elif j == 1: d = "-" elif j == 2: d = "/" else: d = "*" k = b c d e print(k) if you're after variables e on single line, couldn...
Read more

Generic Map Parameter java -

i having lot of methods of type: public static list<eduusers> getdetails(class c, map<string, integer> params) { list<eduusers> details = null; session session = hibernateutil.getsessionfactory().opensession(); transaction tx = null; try { tx = session.begintransaction(); criteria cr = session.createcriteria(c); (map.entry<string, integer> entry : params.entryset()) { cr.add(restrictions.eq(entry.getkey(), entry.getvalue())); } details = cr.list(); tx.commit(); } catch (exception asd) { log.debug(asd.getmessage()); if (tx != null) { tx.commit(); } } { session.close(); } return details; } i trying have generic method them , have written far: public static <t> list<t> getdetails(class<t> c, class<t> b) { l...
Read more

arrays - What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? -

what arrayindexoutofboundsexception mean , how rid of it? here code sample triggers exception: string[] name = {"tom", "dick", "harry"}; for(int = 0; i<=name.length; i++) { system.out.print(name[i] +'\n'); } your first port of call should documentation explains reasonably clearly: thrown indicate array has been accessed illegal index. index either negative or greater or equal size of array. so example: int[] array = new int[5]; int boom = array[10]; // throws exception as how avoid it... um, don't that. careful array indexes. one problem people run thinking arrays 1-indexed, e.g. int[] array = new int[5]; // ... populate array here ... (int index = 1; index <= array.length; index++) { system.out.println(array[index]); } that miss out first element (index 0) , throw exception when index 5. valid indexes here 0-4 inclusive. correct, idiomatic for statement here be: for (int index = 0; index <...
Read more