xml - Get value of node using xmlpath.v2 golang -


i parsing xml document using gopkg.in/xmlpath.v2, , finding trouble... have no problem info single node, or iterator , loop on items getting info. but, case blocked when try info same node on iterating. think example illuminating.
xml:

<warnings>     <warning type="309" shorttext="unfulfilled paid service 1">unable book seat 1</warning>     <warning type="309" shorttext="unfulfilled paid service 2">unable book seat 2</warning>     <warning type="309" shorttext="unfulfilled paid service 3">unable book seat 3</warning> </warnings>

these xpath usin:

xpath := xpathwarning{     warningsbase:       "warnings/warning",     warning:            "",     warningattr:        "@shorttext", }

and way trying value , attribute:

func getwarnings(root *xmlpath.node, xpath xpath_oc) []warning {     warnings := []warning{}     v, _ := xmlpath.compile(xpath.warningsbase)     warningsbaseiter := v.iter(root)     warningsbaseiter.next() {         rawoffer := warningsbaseiter.node()         warning := warning{             value: getstring("", xpath.warning, rawoffer),             attr:  getstring("", xpath.warningattr, rawoffer),         }         warnings = append(warnings, warning)     }     return warnings } func getstring(expressionprefix string, xpathexpression string, node *xmlpath.node) string {     expr := []string{expressionprefix, xpathexpression}     pathstring := strings.join(expr, "")     if pathstring != "blank" {         path, err := xmlpath.compile(pathstring)         if err == nil {             value, _ := path.string(node)             return value         }     }     return "" }

i able shorttext, not value. had been checking error, showing on terminal result of path, err := xmlpath.compile(pathstring), , err shown compiling xml path "":0: empty path.

any solution this??
thanks.

try xquery package supports extract data xml xpath expression.

import (     "github.com/antchfx/xquery/xml" )  xmlstr:=`<?xml version="1.0"?><warnings>...</warnings>` doc, _ := xmlquery.parse(strings.newreader(xmlstr)) nodes:=xmlquery.find(doc,"//warning") _,node:=range nodes{     fmt.println(node.selectattr("shorttext"))     fmt.println(node.innertext) }

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