c++ - When we call function and pass the character array, Why we call it by using character array name? -


i mean when define integer array this-

int main() { int a[100]={0,1,2,3}; cout<<a<<endl; return 0; }

it prints address of 0x69fe74 if pass array function this-

    void fun(int *a) ///getting argument in integer pointer. right.     {      }     int main()     {     int a[100]={0,1,2,3};     cout<<a<<endl;     fun(a); ///function call putting name argument-     return 0;     }

but in character array when this-

int main() { char a[100]={'a','b'}; cout<<a<<endl; return 0; }

it prints elements of character array. output=ab question is- how can pass value function same thing character array how possible?

void fun(char *a) ///getting argument in character pointer. right.     {      }     int main()     {  char a[100]={'a','b'};    cout<<a<<endl;     fun(a); ///function call putting array name argument-     return 0;     }

you this

char s[100] = {'a', 'b'};  std:: cout << (void *) s;

std::cout overloaded 1 way char arrays (to print contents), way pointers (to print address). that's historical reasons. in modern c++ should pass std::string if wish print out series of characters.


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