Ceasars Cipher in Ruby - 


class ceasarscipher def initialize text     @text = text.split '' end  def encrypt key     @text = @text.each |letter|         key.times             if letter != "z"                 letter.next!             else                 letter = "a"             end         end     end end  def printcipher     puts @text end end  cipher = ceasarscipher.new "abcdefghijklmnopqrstuvwxyz" cipher.encrypt 2 cipher.printcipher

when run code output is: c d e f g h j k l m n o p q r s t u v w x y z z z

i don't understand why there z 3 times. thought long time don't it... answers.

it's because when letter = "a" don't change string, instead declare new variable.

here fix using map:

def encrypt key   @text.map! |l|     key.times.reduce(l) |l|       l == 'z' ? 'a' : l.next     end   end end

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