How to make pivot table in SQL Server in my case? -


i wants display record same column. don't know how describe question also.

i have table called soldqtytable

itemno    weeks    years    qtysold    asofweekonhand ---------------------------------------------------- 1           1        2017      5         3 2           1        2017      2         5 3           1        2017      66        70 1           2        2017      4         33

i wants display below

itemno    years    [1qtysold]    [1_onhand]    [2qtysold]    [2_onhand] ----------------------------------------------------------------------- 1          2017       5               3            4            33 2          2017       2               5 3          2017      66               70

i tried in way. doesn't work

select      pvt1.itemid,     pvt1.storeid,     pvt1.years,     isnull([1],0) [1qtysold], isnull([2],0) [2qtysold],     isnull([1_onhand],0) [1_onhand], isnull([2_onhand],0) [2_onhand]  (     select         itemid,         storeid,         years,         weeks,         asofweekonhand             soldqtytable ) l pivot (     sum(asofweekonhand)      weeks in ( [1_onhand], [2_onhand]) ) pvt1 left join (     select         itemid,         storeid,         years,         weeks,         qtysold             soldqtytable ) l pivot (     sum(qtysold)      weeks in ( [1soldqty], [2soldqty] ) pvt2 on pvt2.itemid = pvt1.itemid , pvt1.years = pvt2.years      pvt1.years = 2017

i find conditional aggregation simpler:

select itemid, years,        sum(case when weeks = 1 qtysold end) qtysold_1,                  sum(case when weeks = 1 asofweekonhand end) asofweekonhand_1,        sum(case when weeks = 2 qtysold end) qtysold_2,                  sum(case when weeks = 3 asofweekonhand end) asofweekonhand_2 soldqtytable group itemid, years order itemid, years;

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