python - Why numpy returns true index while comparing integer and float value from two different list -


how avoid returning true index while comparing 10.5 , 10?

a = np.array([1,2,3,4,5,6,7,8,9,10.5])  b = np.array([1,7,10])  = np.searchsorted(a,b)  print   # [0 6 9]

i want places of exact matches: [0 6]

you use np.searchsorted left , right , keep don't return same index both:

>>> import numpy np >>> = np.array([1,2,3,4,5,6,7,8,9,10.5]) >>> b = np.array([1,7,10])  >>> = np.searchsorted(a, b, 'left') >>> j = np.searchsorted(a, b, 'right') >>> i[i!=j] array([0, 6], dtype=int64)

that works because searchsorted returns index element needs inserted if want keep other array sorted. when value present in other array returns index before match (left) , index after matches(right). if index differs there's exact match , if index same there's no exact match


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