What is the execution logic of the expression in C? -


this question has answer here:

suppose couple of expression in c. different outputs provided.

int =2,j; j= + (2,3,4,5); printf("%d %d", i,j); //output= 2 7   j= + 2,3,4,5;  printf("%d %d", i,j);  //output 2 4

how execution take place in both expression , without bracket giving different outputs.

comma operator works evaluating expressions , returning last expression.

j= + (2,3,4,5);

becomes

j= + (5); //j=7

in second expression assignment operator takes precedence on comma operator,so

j= + 2,3,4,5;

becomes

(j= + 2),3,4,5; //j=4

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