Python Regex instantly replace groups -


is there way directly replace groups in regex-syntax.

the normal way:

re.match(r"(?:aaa)(_bbb)", string1).group(1)

yet want achieve this:

re.match(r"(\d.*?)\s(\d.*?)", "(call_group_1) (call_group_2)")

so want build new string instantaneous if possible calling groups regex caught.

have @ re.sub:

result = re.sub(r"(\d.*?)\s(\d.*?)", r"\1 \2", string1)

this python's regex substitution (replace) function. replacement string can filled so-called backreferences (backslash, group number) replaced matched groups. groups counted same group(...) function, i.e. starting 1, left right, opening parentheses.


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