javascript - AngularJS two $http function async return object -


this question has answer here:

i using angularjs of $http function, have 1 async function need other 1 feedback variable , continue ,my code follows:

function getdatalist(company_id) {     return $http.get("https://for_test_document/restful_api/brandsearch/format=json&company_id=" + company_id); } 

then try use follows, json has been received correctly:

for (var = 0; < len; i++) {     getdatalist(json.data[i].id).then(function(successdata) {         var len = successdata.data.length;         var brand_name = "";         (var j = 0; j < len; j++) {             brand_name = brand_name + successdata.data[j].brand_name + '/';         }         console.log(brand_name);         return brand_name + ""     }) 

my question that, console.log have show brand_name correctly, why in browser shows object? the browser show follows

my html follows:

function loadinfo(){     $http({         method:'get',         url:'https://for_example/restful_api/companysearch/?format=json',         datatype: "json",         contenttype : 'application/json',         accept: 'application/json',      }).then(function (json){         get_company_type().then(function (data) {             unique_company_type = data.data          })         /*insert data table */       var len =json.data.length;       var tablestr = '';       tablestr = tablestr+ content       tablestr = tablestr+'<tbody role="alert" aria-live="polite" aria-relevant="all">';         for(var i=0;i<len;i++){             tablestr = tablestr+'<td class=" ">' +        getdatalist(json.data[i].id).then(function (successdata){                             var len = successdata.data.length;                                         var brand_name = "" ;                                                   for(var j=0;j<len;j++){                                                brand_name = brand_name +successdata.data[j].brand_name+'/';                                }                                              console.log(brand_name);                                               return brand_name + "" }) +                                              '</td><td class=" ">' +json.data[i].city  + '</td><td class=" ">' +json.data[i].address + '</td><td class=" ">' +'client contact'  +                  '</td><td class=" ">' + 'contact details' + "</td></tr>";         }       tablestr = tablestr+"</tbody>"; 

thanks helps.

clearly returns object of type brand_name, not sure it's supposed that. can try parse forcibly string using tostring() :

for (var = 0; < len; i++) {     getdatalist(json.data[i].id).then(function(successdata) {         var len = successdata.data.length;         var brand_name = "";         (var j = 0; j < len; j++) {             brand_name = brand_name + successdata.data[j].brand_name.tostring() + '/';         }         console.log(brand_name);         return brand_name + ""     }) 

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