javascript - AnguarJS won't even run $scope message -


having issue angular doesn't seem working @ in app.

trying run message on index page maincontroller, , won't run this.

jsfiddle: https://jsfiddle.net/cj5pe43k/1/.

html:

<body ng-app="app" ng-controller="maincontroller">      <div id="test" style="position:absolute;top:0;left:0;background:#000;width:100vw;height:100vh;color:#fff;display:flex;align-items:center;justify-content:center;"><p>{{message}}</p></div>      <script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>  </body>

js:

var app = angular.module('app', ['ngroute']);  app.config(function($routeprovider) {     $routeprovider      .when('/', {         templateurl: 'index.html',         controller: 'maincontroller'     })      .when('/', {         templateurl: 'pages/home.html',         controller: 'maincontroller'     }) })  app.controller('maincontroller', function($scope) {     $scope.message = 'main controller active'; })

after checking jsfiddle, seems including angular-ui-router, despite typing code ngroute. error returned fiddle little bit hidden clear: can't find ngroute module. , attached files having angular-ui-router included.

are following these steps? https://docs.angularjs.org/api/ngroute

if want include ui router, please have here instead: https://ui-router.github.io/ng1/docs/latest/index.html#/api/ui.router


Comments

Post a Comment

Popular posts from this blog

python - Operations inside variables -

this question has answer here: evaluating mathematical expression in string 12 answers i want make python script finds maximum possible output using 2 operations. problem says there syntax error @ 2nd last line, in b in there. how can fix it? x = 0 = int(input("1st number:")) c = int(input("2nd number:" )) e = int(input("3rd number:" )) in range(4): if == 0: b = "+" elif == 1: b = "-" elif == 2: b = "/" else: b = "*" j in range(4): if j == 0: d = "+" elif j == 1: d = "-" elif j == 2: d = "/" else: d = "*" k = b c d e print(k) if you're after variables e on single line, couldn...
Read more

Generic Map Parameter java -

i having lot of methods of type: public static list<eduusers> getdetails(class c, map<string, integer> params) { list<eduusers> details = null; session session = hibernateutil.getsessionfactory().opensession(); transaction tx = null; try { tx = session.begintransaction(); criteria cr = session.createcriteria(c); (map.entry<string, integer> entry : params.entryset()) { cr.add(restrictions.eq(entry.getkey(), entry.getvalue())); } details = cr.list(); tx.commit(); } catch (exception asd) { log.debug(asd.getmessage()); if (tx != null) { tx.commit(); } } { session.close(); } return details; } i trying have generic method them , have written far: public static <t> list<t> getdetails(class<t> c, class<t> b) { l...
Read more

arrays - What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? -

what arrayindexoutofboundsexception mean , how rid of it? here code sample triggers exception: string[] name = {"tom", "dick", "harry"}; for(int = 0; i<=name.length; i++) { system.out.print(name[i] +'\n'); } your first port of call should documentation explains reasonably clearly: thrown indicate array has been accessed illegal index. index either negative or greater or equal size of array. so example: int[] array = new int[5]; int boom = array[10]; // throws exception as how avoid it... um, don't that. careful array indexes. one problem people run thinking arrays 1-indexed, e.g. int[] array = new int[5]; // ... populate array here ... (int index = 1; index <= array.length; index++) { system.out.println(array[index]); } that miss out first element (index 0) , throw exception when index 5. valid indexes here 0-4 inclusive. correct, idiomatic for statement here be: for (int index = 0; index <...
Read more