swift - How can I sort an array of strings based on the number of instances a string appears in an element? -


how can sort array of strings based on number of instances string appears in element? example:

let str = "o" let arrayofstrings = ["hot", "only open on tuesdays", "people of earth"]  //sort here  //arrayofstring becomes ["only open on tuesdays", "people of earth", "hot"] 

import foundation let str = "o" var arrayofstrings = ["hot", "only open on tuesdays", "people of earth"]  arrayofstrings.sort {   return $0.components(separatedby: str).count < $1.components(separatedby: str).count }  print(arrayofstrings) // ["hot", "only open on tuesdays", "people of earth"]

note correct order if sort highest instances last. went least instances show this: string "o" , string "o" 2 different strings count in original array 1, 2, 2. if want compare strings case-insensitively have apply uppercase or lowercase operation comparison.

here result instances of string first, using case-insensitive comparison:

arrayofstrings.sort {   let upper = str.uppercased()   return $0.uppercased().components(separatedby: upper).count >     $1.uppercased().components(separatedby: upper).count }  print(arrayofstrings) // ["only open on tuesdays", "people of earth", "hot"]

Comments

Post a Comment

Popular posts from this blog

python - Operations inside variables -

this question has answer here: evaluating mathematical expression in string 12 answers i want make python script finds maximum possible output using 2 operations. problem says there syntax error @ 2nd last line, in b in there. how can fix it? x = 0 = int(input("1st number:")) c = int(input("2nd number:" )) e = int(input("3rd number:" )) in range(4): if == 0: b = "+" elif == 1: b = "-" elif == 2: b = "/" else: b = "*" j in range(4): if j == 0: d = "+" elif j == 1: d = "-" elif j == 2: d = "/" else: d = "*" k = b c d e print(k) if you're after variables e on single line, couldn...
Read more

Generic Map Parameter java -

i having lot of methods of type: public static list<eduusers> getdetails(class c, map<string, integer> params) { list<eduusers> details = null; session session = hibernateutil.getsessionfactory().opensession(); transaction tx = null; try { tx = session.begintransaction(); criteria cr = session.createcriteria(c); (map.entry<string, integer> entry : params.entryset()) { cr.add(restrictions.eq(entry.getkey(), entry.getvalue())); } details = cr.list(); tx.commit(); } catch (exception asd) { log.debug(asd.getmessage()); if (tx != null) { tx.commit(); } } { session.close(); } return details; } i trying have generic method them , have written far: public static <t> list<t> getdetails(class<t> c, class<t> b) { l...
Read more

arrays - What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? -

what arrayindexoutofboundsexception mean , how rid of it? here code sample triggers exception: string[] name = {"tom", "dick", "harry"}; for(int = 0; i<=name.length; i++) { system.out.print(name[i] +'\n'); } your first port of call should documentation explains reasonably clearly: thrown indicate array has been accessed illegal index. index either negative or greater or equal size of array. so example: int[] array = new int[5]; int boom = array[10]; // throws exception as how avoid it... um, don't that. careful array indexes. one problem people run thinking arrays 1-indexed, e.g. int[] array = new int[5]; // ... populate array here ... (int index = 1; index <= array.length; index++) { system.out.println(array[index]); } that miss out first element (index 0) , throw exception when index 5. valid indexes here 0-4 inclusive. correct, idiomatic for statement here be: for (int index = 0; index <...
Read more