How can I calculate the expression "A = D[2] – D[4] " in MIPS assembly language? -


i have been learning assembly language (mips) couple of weeks (so suppose new @ this) , have found myself being confused using arrays , right registers when try code in assembly language.

at moment trying program this:

a program supposed calculate , print out values of following expression: = d[2] – d[4] has "d" array 10 words , "a" array 1 word.

this have coded far , don't know how calculate value of "x" here. hope question clear enough! please clarify in comments if not :) :)

    #  variable in register $s1     #  base address of array d in $s2         #allocating array        .data        .align  2                    d: .word  10, 11, 12, 13, 14, 15, 16, 17, 18, 19                        .space  320                    #main function        .text        .globl main        main:                  addu  $s7, $0, $ra              #calculate value of           #this value of supposed calculated.       #first load number @ d[3] temporary register can       #be calculated later    = number in index (position) 3      #then load number @ d[5] temporary register can       #be calculated later    = number in index (position) 5      #then subtract results, d[3] - d[5]. = number @       #position 3 - number @ position 5      # finally, should value of "a"         la $t0, d #put base address of array d $t0     lw $t2, 3 #load index "3" $t2     lw $t3, 5 #load index "5" $t3     sub $s1, $t2, $t3 #a = d[3] - d[5]                      #print value of      .data      .globl  message1        message1:  .asciiz "\nthe value of is: "        .text      li  $v0, 4            # print string      la  $a0, message1           syscall      li  $v0, 1            # print interger      add  $a0, $0, $s1     # print value of       syscall         #end of main       addu  $ra, $0, $s7     # restore return address       jr    $ra              # return main program 


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