python - Sum All elements of each array in an array of arrays -


i have dictionary:

import numpy np dict={'w1': np.array([[ 1.62434536, -0.61175641, -0.52817175],                       [-1.07296862,  0.86540763, -2.3015387 ]]),       'b1': np.array([[ 1.74481176],                       [-0.7612069 ]]),       'w2': np.array([[ 0.3190391 , -0.24937038],                       [ 1.46210794, -2.06014071],                       [-0.3224172 , -0.38405435]]),       'b2': np.array([[ 1.13376944],                       [-1.09989127],                       [-0.17242821]]),       'w3': np.array([[-0.87785842,  0.04221375,  0.58281521]]),       'b3': np.array([[-1.10061918]])}

i need sum elements of w1, w2, w3 after squared them, each 1 @ time of three.

i used extract list keys w(i)

l=[v k, v in dict.items() if 'w' in k]

how sum of squared elements in each array? when taken each array separately do:

 np.sum(np.square(l[0]) 10.4889815722 l[0]

i don't know though how sum them in 1 shot

i'm not sure got you, here's think you're looking for:

>>> import numpy np >>> data = [np.array([1.62434536, -0.61175641, -0.52817175]), np.array([-1.07296862, 0.86540763, -2.3015387])] >>> [np.sum(arr) arr in data] [0.48441719999999999, -2.5090996900000002]

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