python - Index of matching bracket character within a lambda function? -

i'm more curious in dire need. possible pass lambda function 2 arguments s, , i. s string in question , i index of first bracket; , have return index of complimentary bracket?

i should note needs work brackets (), , not {} or [].

for example

>>> f( '(() foo ) bar' , 0) 8 

f defined lambda function

edit: i'm aware numerous methods exist finding matching bracket. i, however, curious if can simplified lambda expression.

i'm far lazy worry corner cases, using itertools.accumulate it's relatively straightforward:

f = lambda s,i: next((i i,x in enumerate(accumulate     ({'(': 1, ')': -1}.get(c,0) c in s[i:]), i) if not x), none)  in [31]: s = '(() foo ) bar'  in [32]: f(s, 0) out[32]: 8  in [33]: f(s, 1) out[33]: 2  in [34]: f(s, 2) 

this works tracking height of string, counting ( +1 , ) -1:

in [36]: list(accumulate({'(': 1, ')': -1}.get(c,0) c in s)) out[36]: [1, 2, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0]